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/* THIS PROGRAM IS TO ASK USER TO INPUT TWO DATE & PRODUCE A NEW DATE */#include #include struct date { int dd; int yy; int mm; };date add(date d1,date d2) { date temp; temp.dd=d1.dd+d2.dd; temp.mm=d1.mm+d2.mm; temp.yy=d1.yy+d2.yy; if(temp.dd>=30) { temp.dd-=30; temp.mm++; } else if(temp.dd>=31) { temp.dd-=31; temp.mm++; } else if(temp.dd>=28) { temp.dd-=28; temp.mm++; } if(temp.mm>=12) { temp.mm-=12; temp.yy++; } return temp; }void main() { clrscr(); date d1,d2,ans; cout<<" enter the 1st date (dd/mm/yyyy) "; cin>>d1.dd; cin>>d1.mm; cin>>d1.yy; cout<<" enter the 2nd date (dd/mm/yyyy) "; cin>>d2.dd; cin>>d2.mm; cin>>d2.yy; ans=add(d1,d2); cout<<" new date:-"< }
limitations of single iheritance
Insert values in queue - C++ program: Write a program to insert values in queue. int main() { int k; Queue timeLine; cout for(
Static Variables Static variables have the similar scope s automatic variables, but, unlike automatic variables, static variables retain their values over number of function ca
how we can code in c++ for assignment problem (operation research) method to mkinimization and mamization
Develop a C++ program that uses a while to determine the gross pay (in Dollars) for each of several employees. The company pays “straight-time” for the first 40 hours worked by ea
Byteland county is very famous for luminous jewels. Luminous jewels are used in making beautiful necklaces. A necklace consists of various luminous jewels of particular colour. Nec
A: No. Syntax wise it is permitted. But then the function is no longer Inline. Since the compiler will never know how deep the recursion is at compilation time.
Assume we wish to partition the square roots of the integers from 1 to 100 in to two piles of fifty numbers every, such that the sum of the numbers in the first pile is as close as
Expected output of the program: 1. Consider the following programs. For each, indicate whether the program is correct. If yes, what is the expected output? If not, what is the
#include using namespace std; void print(int marks_arr[],int cnt) { int ind[cnt]; int i=0; int j=0; int k=0; int s=0; for(k=0;k { ind[k]=0; } int cnt1=0; for(i=0;i
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