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Write a program that counts from 0 to 99 and prints these numbers to the terminal ie it prints 00, 01, 02, 03, 04, 05, ....,99.
Graphics
1. Write a program in rPeANUt that fills the graphics display with white and then halts.
Interrupts
1. Write an interrupt handler for the trap instruction that outputs to the terminal the string 'trap'. In the main program call this trap in an infinite loop.
2. Modify the handler for the trap instruction such that it implements the system calls 'read' and 'write'. The 'read' system call will read a single character from the terminal (make it blocking), the 'write' system call will write a single character to the terminal. Use register R0 for telling the handler which system call it is (say if the value 0 is in R0 then it is the 'read' system call, and if the value 1 is in register R0 then it is the 'write' system call). Also in the case of 'write' use register R1 to store the character to be written. In the case of 'read' use register R1 for the place the read character is returned.
Program is to define a class as student: Program is to define a class as student and display the records specific depending upon the number class student { private:
answer
Q: When should you employ multiple inheritance? A:There are three acceptable answers:- "Rarely," "Never," and "while the problem domain cannot be modeled accurately any
Converting Base Type to Class Type (char to string) class String { char *name; int length; public: String(void) {length =0; name = new char[length+1];
Implementation of the Definition class: void Definition::put_word(char *s) { word = new char[strlen(s)+1]; strcpy(word,s); nmeanings = 0; } voi
HOW TO USE POINTER
What is conversion operator? Explain it with example.
Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b.
Using a Friend Using a friend function is quite easy. The following example explains a friend function to access members of two classes. class Bclass;
Threaded binary tree: Consider the linked illustration of a binary tree 'T. Approximately half of the entries is the pointer fields 'LEFT' and 'RIGHT' will have null elements. Th
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