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A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
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Sketch the graph of h (t ) = 1 - 5e 1/(t/2) Solution : Let's primary get a table of values for this function. Following is the sketch. The major point behin
SOLVE AND GRAPH THE PARABOLA NOTE: WRITE YOUR SOLUTIONS AND COMPLETE EQUATION OF GRAPH SPOINTS EACH 1. V(0,0) (0.2) P-2 2. V(0,0) E-5,0) P=-5 3. V(4-3) F(4,-2) P=1 4. V-1,5)
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Michael made 19 out of 30 free-throws this basketball season. Larry's freethrow average was 0.745 and Charles' was 0.81. John made 47 out of 86 free-throws. Who is the best free-th
Sol. A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
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