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A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
A speaks truth in 80% of the cases and B speaks truth in 60% of the cases. Find out the probability of the cases of which they are possible to contradict each other in stating sim
2-3+=3+-4
Factoring out the greatest common factor of following polynomials. 8x 4 - 4 x 3 + 10 x 2 Solution Primary we will notice that we can factor out a
I have 6 cups of patatos that I have to share with 13 friends write that as the nearest hundredth
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Solve for x: 4 log x = log (15 x 2 + 16) Solution: x 4 - 15 x 2 - 16 = 0 (x 2 + 1)(x 2 - 16) = 0 x = ± 4 But log x is
an insurance salesman sells policies to 5 men, all of identical age in good health. the probability that a man of this particular age will be alive 20 years hence is 2/3.Find the p
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Example of Exponential Smoothing By using the previous example and smoothing constant 0.3 generate monthly forecasts Months Sales Forecast
a business is owned by three people.the first owns 1/12 of the business and the second owns 1/6 of the business. what fractional part of the business is owned by the third person
Sol. A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
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