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A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
what is the first step
Determine the second derivative for following functions. Q (t ) = sec (5t ) Solution : Following is the first derivative. Q′ (t
Give the Introduction to Scientific Notation? In mathematics, it can be very difficult and time-consuming to do calculations involving very large and very small numbers. This i
There are m months in a year, w weeks within a month and d days in a week. How many days are there in a year? In this problem, multiply d and w to obtain the total days in one
Determine how many different words can be formed out of the letters of the word VARANASI? Ans: 720 different words can be formed out of the letters of the word VARANASI.
Optimization : In this section we will learn optimization problems. In optimization problems we will see for the largest value or the smallest value which a function can take.
what is tan 45 degrees?
HOW TO ADD MIXED FRACTION
Example of addition of Fractions: 105/64 + 15/32 + 1/6 =____ would require the denominator to be equal to 64 x 32 x 6 = 12,288. This type of number is very hard to use.
Q. Find Probability of tossing a head with the dime? List the sample space, and find n(S), for the outcomes of tossing a nickel followed by a dime. What is the probability of t
Sol. A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
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