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A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
kolushushi borrowed tsh 250000/- and paid135000/- as interest in 3 years. what rate of interest was paid
Solving Algebraic Word Problems: What are the capacities of two water storage tanks in a nuclear facility if one holds 9 gallons less than three times another, and their whole
the length of three pieces of ropes are 140cm,150cm and 200cm.what is the greatest possible length to measure the given pieces of a rope?
what is the least number of faces and bases the paperweight could have?
Negative Skewness It is an asymmetrical curve whether the long tail extends to the left NB: In developed countries this frequency curve for the age distribution is charact
A sell a watch to B at gain of 20% and B sell to C at loss of 10%. if C pays @ 432, how much did A pays for it.
The following exercises may help you to look more closely at the activities done above. E1) Why did the two dice game become more difficult? E2) Do you find the activities in
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ALGORITHM FOR DIVISION : If you ask a 10 or 1 1-year-old child to solve, say, 81 + 9, the chances are that she will correctly do it. But if you ask her to solve, say 72 + 3, t
Arc Length with Vector Functions In this part we will recast an old formula into terms of vector functions. We wish to find out the length of a vector function, r → (t) =
Sol. A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
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