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A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7
Nick paid $68.25 for a coat, including sales tax of 5%. What was the original price of the coat before tax? Since 5% sales tax was added to the cost of the coat, $68.25 is 105%
Computation of Covariance Ungrouped Data For a population consisting of paired ungrouped data points {X, Y} where,
Solving for X in isosceles triangles
Steps for Alternating Series Test Suppose that we have a series ∑a n and either a n = (-1) n b n or a n = (-1) n+1 b n where b n > 0 for all n. Then if, 1.
A B C play a game. If chance of their winning it in an attempt arr2/3, 1/2, 1/4 respective. A has a first chance followed by Band Called respective chances of winning the game.
Simplify the Boolean function: F (w,x,y,z) = ∑ (0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) (8) Ans: f(w, x, y, z) = ∑(0, 1, 2, 3, 4, 6, 8, 9, 12, 13, 14) The above
A bag contains 19 tickets, numbered from 1 to 19. A ticket is drawn and then another ticket is drawn without replacement .Find the probability that both tickets will show even numb
What is Identities and Contradictions ? Look at this equation: x + 1 = 1 + x It happens to be true always, no matter what the value of x. (Try it out! What if x is 43?)
a computerized payroll package and its cost,futures and the size of the business and how business mathematics is an inbuilt component of the package
let R be a (noncommutative) ring. Given that a,b and a+b ? R are all units, prove that a^(-1)+b^(-1) is a unit
Sol. A non - leap year contains 365 days 52 weeks and 1 day more.i) We get 53 Sundays when the remaining day is Sunday.Number of days in week = 7∴ n(S) = 7Number of ways getting 53 Sundays.n(E) = 1n E 1n S 7=∴ Probability of getting 53 Sundays =1/7
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