Probability that a leap year will have 53 sunday?explain, Mathematics

Assignment Help:

A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following : (i) Sunday and Monday (ii) Monday and Tuesday (iii) Tuesday and Wednesday (iv) Wednesday and Thursday (v) Thursday and Friday (vi) Friday and Saturday (vii) Saturday and Sunday For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday. n(S) = 7 n(E) = 2 P(E) = n(E) / n(S) = 2 / 7

Related Discussions:- Probability that a leap year will have 53 sunday?explain

The perimeter square can be expressed as x + 4 estimate x, The perimeter of...

The perimeter of a square can be expressed as x + 4. If one side of the square is 24, what is the value of x? Since the perimeter of the square is x + 4, and a square has four

Simplify, 3 3/4+(1 1/49*7/10)

3 3/4+(1 1/49*7/10)

Holistic marketing , Necessity of holistic marketing or importance of holis...

Necessity of holistic marketing or importance of holistic marketing

Parabola, If the point (a,2a) is an interior point of the region bounded by...

If the point (a,2a) is an interior point of the region bounded by the parabola y2=16x and the double ordinate through the focus then a belongs to

Prealgebra, ion..

ion..

Multiples, The sum of the smallest and largest multiples of 8 up to 60 is?

The sum of the smallest and largest multiples of 8 up to 60 is?

Trigonometry, what are reason inside a circle?

what are reason inside a circle?

DIVITE, 20348876567

20348876567

Triganometry, Ask question #Minimum 100 words what is the hypotunus of a r...

Ask question #Minimum 100 words what is the hypotunus of a right bangled triangle a=5@ b=25 find c accwhepted#

Repeated eigenvalues, It is the last case that we require to take a look at...

It is the last case that we require to take a look at. During this section we are going to look at solutions to the system, x?' = A x? Here the eigenvalues are repeated eigen

3/7/2013 5:13:25 AM Sol. A non - leap year contains 365 days 52 weeks and 1 day more. i) We get 53 Sundays when the remaining day is Sunday. Number of days in week = 7 ∴ n(S) = 7 Number of ways getting 53 Sundays. n(E) = 1 n E 1 n S 7 = ∴ Probability of getting 53 Sundays =1/7
3/7/2013 5:13:41 AM Sol. A non - leap year contains 365 days 52 weeks and 1 day more. i) We get 53 Sundays when the remaining day is Sunday. Number of days in week = 7 ∴ n(S) = 7 Number of ways getting 53 Sundays. n(E) = 1 n E 1 n S 7 = ∴ Probability of getting 53 Sundays =1/7

3/7/2013 5:13:25 AM

Sol. A non - leap year contains 365 days 52 weeks and 1 day more.
i) We get 53 Sundays when the remaining day is Sunday.
Number of days in week = 7
∴ n(S) = 7
Number of ways getting 53 Sundays.
n(E) = 1
n E 1
n S 7
=
∴ Probability of getting 53 Sundays =1/7

3/7/2013 5:13:41 AM

Write Your Message!

Name

Email id

Message

Verfication Code

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

Submit Assignment

User Account

All Pages