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TWO PERSONS A AND B AGREE TO MEET AT A PLACE BTWEEN 11 TO 12 NOON. THE FIRST ONE TOARRIVE WAITS FOR 20 MIN AND THEN LEAVE. IF THE TIME OF THIR ARRIVAL BE INDEPENDET AND AT RNDOM,THEN THE PROBABILITY THAT A AND B MEET IS[A]1/3 [B]2/3 [C]4/9 [D]5/9ANSWER: [A]
AS THE FIRST PERSON TO ARRIVE WAITS FOR 20 MINUTES N(E)=20
TOTAL TIME IS 1 HOUR SO N(S)=60
THE OTHER PERSON HAVE TO ARRIVE IN THAT 20 MINUTES
THEREFORE PROBABILITY=20/60=1/3
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Illustrates that the following numbers aren't solutions to the given equation or inequality. y = -2 in 3( y + 1) = 4 y - 5 Solution In this case in essence we do the sam
Sir, I am a Maths teacher from kolkata,India.i want to join your website as Maths'' expert.Please guide me as to how to join your website and earn some money. I will be really grat
how to answer this: 3x2-18x-60
Differentiate y = x x Solution : We've illustrated two functions similar to this at this point. d ( x n ) /dx = nx n -1 d (a x ) /dx= a
A polynomial satisfies the following relation f(x).f(1/x)= f(x)+f(1/x). f(2) = 33. fIND f(3) Ans) The required polynomial is x^5 +1. This polynomial satisfies the condition state
f(x)=sin(x),All x belongs to [p/6, p]
zeroes of polynomial 2x2-3x-2
Define transportation problem
It is the catch all force. If there are some other forces which we decide we need to act on our object we lump them in now and call this good. We classically call F(t) the forcing
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