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Postorder traversal of a binary tree
struct NODE
{
struct NODE *left;
int value; /* can take any data type */
struct NODE *right;
};
postorder(struct NODE *curr)
if(curr->left != NULL) postorder(curr->left);
if(curr->right != NULL) postorder(curr->right);
printf("%d", curr->value);
}
In a preorder traversal, first (pre) the root is visited and then the left & right sub- trees are traversed. In a postorder traversal, first the left sub-tree is visited, followed by right sub-tree which is then followed through root. In inorder traversal, first the left sub- tree is visited, followed by root, followed by right sub-tree.
This method is the reverse of FIFO and assumes that each issue of stock is made from latest items received in the enterprises .Thus if the last lot to be received is not sufficient
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for(int i = 0; i for (int j = n - 1; j >= i ; j--){ System.out.println(i+ " " + j);
Advantages of dry running a flowchart When dry running a flowchart it's advisable to draw up a trace table illustrating how variables change their values at every stage in the
1. In computer science, a classic problem is how to dynamically store information so as to let for quick look up. This searching problem arises frequently in dictionaries, symbol t
A binary search tree is used to locate the number 43. Which of the following probe sequences are possible and which are not? Explain. (a) 61 52 14 17 40 43 (b) 2 3 50 40 60 43 (c)
how to implement prims algorithm dynamically
explain the prims''s algorithm with suitable example?
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