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Equation of line joining(0,0)and point of intersection of X2+Y2+2XY=4 , 3x2+5y2-xy=7 is solution) The two equations above represent pair of straight lines. We can complete the square and arrive at the 4 line equatons and find their point of intersecrtion.Simple method (by mere observation) we can say X=1&Y=1 satisfies both the equation.therfore, Line passing through origin and (1,1) is :X=Y.=>X=Y is the reqd line equation
A man travels 600km partly by train and partly by truck. If he covers 120km by train and the rest by truck, it takes him eight hours. But, if he travels 200km by train and the res
Minima, Maxima and points of inflexion a) Test for relative maximum Consider the given function of x whose graph is presented by the figure given below
Katie's school has a rectangular courtyard whose area can be expressed as 3x 2 - 7x + 2. Which of the following could be the dimensions of the courtyard in terms of x? Since t
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(a) Convert z = - 2 - 2 i to polar form. (b) Find all the roots of the equation w 3 = - 2 - 2 i . Plot the solutions on an Argand diagram.
Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique) A=bq+r, where o ≤ r 48=18x2+12 18=12x1+6 12=6x2+0 ∴ HCF (18,48) = 6 now 6
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