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If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be, If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be,
Fm = 1/4∏€ X q1q2/r2 -------------------------------------(2)
Dividing equations 1 and 2 we get F/Fm = € / €0 = € r. This ratio is called as relative permittivity or dielectric constant. This is equal to 1 in air. Hence the force between two charges depends on the medium in which they are situated.
1. You now pass the signal + interference through a 2-section 1.0 kHz low pass filter with a rolloff of 40 dB/decade. Make a plot of the waveform of the filter output over the time
The shear force of a cantilever beam of length L carrying a uniformaly distributed load W Per unit length is how much at fixed end
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In a young's double slit experiment a point on the screen is similar distance from both the slits if any one of the slit is closed the intensity at P due to the other slit is 0.02
terminal velocity
Soft Ferromagnetic substances: Those substances that lose their magnetism are known as soft magnetic substances such as soft iron.
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Briefly explain with necessary theory how you will calculate refractive index of water/transparent liquid by using Newton's ring apparatus?
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