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If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be, If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be,
Fm = 1/4∏€ X q1q2/r2 -------------------------------------(2)
Dividing equations 1 and 2 we get F/Fm = € / €0 = € r. This ratio is called as relative permittivity or dielectric constant. This is equal to 1 in air. Hence the force between two charges depends on the medium in which they are situated.
The resultant of two forces 3P and 2P is R. If the first force is doubled then the resultant is also doubled. then the angle between the two forces us. plz xplain with the solution
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for 2013
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