Permittivity of the medium, Physics

Assignment Help:

If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be, If the charges are situated in a medium of permittivity ε, then the magnitude of the force between them will be,              

    Fm  =  1/4∏€  X q1q2/r2        -------------------------------------(2)

Dividing equations 1 and 2 we get F/Fm =  € / €0  =  € r. This ratio is called as relative permittivity or dielectric constant.  This is equal to 1 in air. Hence the force between two charges depends on the medium in which they are situated. 


Related Discussions:- Permittivity of the medium

Atom, what is an atom

what is an atom

Viscosity of liquid, How to determine the co efficient of viscosity of liqu...

How to determine the co efficient of viscosity of liquid by capillary flow method?

Magnitude of a point charge, a) Two charges of the value 15X10 -9 coulomb ...

a) Two charges of the value 15X10 -9 coulomb and 30X10 -9 coulomb are locate at a distance 6 cm. Determine the intensity of electric field at point which is at a distance 2 cm fro

How much does automotive oil weigh, How much does automotive oil weigh? ...

How much does automotive oil weigh? As rough guide engine oil generally weighs about 0.87 kg/litre or about 7.2 pounds per US gallon unfortunately a rough answer is the best th

Working model, sir, I am in class xii and i have to submit a project:workin...

sir, I am in class xii and i have to submit a project:working model on any topic in physics. so please help me figure this out

Buoyant Force, I need help with the Fb = F2-F1 formula that used in buoyant...

I need help with the Fb = F2-F1 formula that used in buoyant force

Define magnetic field half way between axis and outside edge, A copper rod ...

A copper rod which is 1 centimetre in diameter carries a current of 5 amps.  The current is distributed uniformly throughout the rod.  The magnetic field half way between the axis

Dielectric constant of the material filling the gap, a) How much charge sho...

a) How much charge should be placed on it to raise its potential to 10,000 V. b)  A parallel plate capacitor having plate area 100 cm 2 and separation 1.0 mm holds a charge of

Calculate the potential differences across each resistor, Q. In the given c...

Q. In the given circuit, calculate the potential differences across each resistor Solution : i) R s = R 1 + R 2 + R 3 = 10Ω ii) Current in circuit I = V/R s

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd