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Parallel to the line specified by 10 y + 3x= -2
In this case the new line is to be parallel to the line given by 10 y ? 3x ? -2 and so it have to have the similar slope as this line. Thus we know that,
m 2 =- 3/10
Now, we've got a point on the new line, (8, 2) ,& we know the slope of the new line, - 3, so ,we can employ the point-slope form of the line to write down the equation of the new line. Following is the equation,
y= 2 - 3/10 ( x - 8)
= 2- 3/10x + 24/10
= - 3/10x +44/10
y = -(3/10)x+22/5
samuel left mauritius at 22:30 on saturday and travelled to london (GMT) for 14h30min he had a stopover for 4 h in london and he continued to travel to toronto for another 6h20min
((1/x^1/2-(x-1)^1/2)+(1/(5-3(x-1)^2)^1/2)
2, -8, 32, -128, ?, ?, ?, what are these next 3?
How do we add integers
I should have an account balance for $50.96. You took out $50.96 for a product on 6/18 which was NOT downloaded or delivered as it not available in the time frame I needed it. I am
1/sec A+tan A =1-sin A /cos A
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Translate the following formula into a prefix form expression in Scheme: 5+4*(6-7/5)/3(14-5)(3+1)
tanx dx
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