#Padovan string, C/C++ Programming

Assignment Help:

A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of the characters ‘X’ , ‘Y’ and ‘Z’ only, and given value of n, write a program that counts the number of occurrences of the string in the n-th Padovan string P(n)

 

program in java

// aakash , suraj , prem sasi kumar kamaraj college
program 1 :

package test.padovanstring;

public class PadovanString {
    public int stringOccurrences(int n, String str){
   
    if(n >= 40)
    return -1;
    if(str.replaceAll("X|Y|Z","").length()>0)
    return -1;
    String res=pad(n);
    return(res.length() - res.replaceAll(str,"").length())/(str.length());
    }
public String pad(int n){
    if(n == 0) return "X";
    if(n == 1) return "Y";
    if(n == 2) return "Z";
    else return pad(n-2) + pad(n-3);
   
}
    public static void main(String []args)
    {
        PadovanString p = new PadovanString();
        System.out.println(p.stringOccurrences(21,"YZ"));
    }
}

 

 

 

Program set 2 :

import java.util.Scanner;

import java.util.ArrayList;

 

public class PadovanSeries

{

    public static void main(String[] arg)

    {

        Scanner read = new Scanner(System.in);

        System.out.println("Enter starting no. : ");

        int start = read.nextInt();

        System.out.println("Enter ending no. : ");

        int end = read.nextInt();

        int[] ans = getSeries(start, end);

        System.out.println("Padovan series : ");

        for (int a : ans)

            System.out.print(a + " ");

    }

 

    public static int[] getSeries(int s, int e)

    {

        ArrayList list = new ArrayList();

        int i, j = 0;

        for (i = s; i <= e; i++, j++)

            list.add(getPadovan(i));

        int[] ans = new int[j];

        for (i = 0; i < j; i++)

            ans[i] = list.get(i);

        return ans;

    }

 

    public static int getPadovan(int p)

    {

        if (p == 0 || p == 1 || p == 2)

            return 1;

        return (getPadovan(p - 2) + getPadovan(p - 3));

    }

}

 

Padova

.


Related Discussions:- #Padovan string

Questions on functions, Write a function for finding out highest and lowest...

Write a function for finding out highest and lowest marks obtained by a student from an array contained student name and marks. For Example : GetHighestLowestMarks{Student{n}, Ma

Rules of function, Rules of function: Inline function created witho...

Rules of function: Inline function created without prototype it reduces the memory and it is used only for small function. Inline function cannot have recursion, static var

Atm program, Ask quIn this assignment you will create an ATM Machine progra...

Ask quIn this assignment you will create an ATM Machine program (using C++) that allows a user to choose one of the following introduction menu items: 1) Create a bank account by

After p = new fred[n], After p = new Fred[n], how does the compiler know ab...

After p = new Fred[n], how does the compiler know about n objects to be destructed throughout delete[] p? A:  The run-time system hold the number of objects, n, somewhere where

Output, i need my home work

i need my home work

I want a reverse engineer a .exe to obtain the code, I want a Reverse engin...

I want a Reverse engineer a .exe to obtain the code Project Description: I'd like to get the full C++ source code from a .exe please Skills required is C++ Programming

Android - iphone mobile game, I am seeking a developer to create a mobile g...

I am seeking a developer to create a mobile game for me. I want an endless runner game with simple controls. The game needs to be a 3D game in a 2D view. The graphics and animation

., what is polymorphism

what is polymorphism

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd