#Padovan string, C/C++ Programming

Assignment Help:

A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of the characters ‘X’ , ‘Y’ and ‘Z’ only, and given value of n, write a program that counts the number of occurrences of the string in the n-th Padovan string P(n)

 

program in java

// aakash , suraj , prem sasi kumar kamaraj college
program 1 :

package test.padovanstring;

public class PadovanString {
    public int stringOccurrences(int n, String str){
   
    if(n >= 40)
    return -1;
    if(str.replaceAll("X|Y|Z","").length()>0)
    return -1;
    String res=pad(n);
    return(res.length() - res.replaceAll(str,"").length())/(str.length());
    }
public String pad(int n){
    if(n == 0) return "X";
    if(n == 1) return "Y";
    if(n == 2) return "Z";
    else return pad(n-2) + pad(n-3);
   
}
    public static void main(String []args)
    {
        PadovanString p = new PadovanString();
        System.out.println(p.stringOccurrences(21,"YZ"));
    }
}

 

 

 

Program set 2 :

import java.util.Scanner;

import java.util.ArrayList;

 

public class PadovanSeries

{

    public static void main(String[] arg)

    {

        Scanner read = new Scanner(System.in);

        System.out.println("Enter starting no. : ");

        int start = read.nextInt();

        System.out.println("Enter ending no. : ");

        int end = read.nextInt();

        int[] ans = getSeries(start, end);

        System.out.println("Padovan series : ");

        for (int a : ans)

            System.out.print(a + " ");

    }

 

    public static int[] getSeries(int s, int e)

    {

        ArrayList list = new ArrayList();

        int i, j = 0;

        for (i = s; i <= e; i++, j++)

            list.add(getPadovan(i));

        int[] ans = new int[j];

        for (i = 0; i < j; i++)

            ans[i] = list.get(i);

        return ans;

    }

 

    public static int getPadovan(int p)

    {

        if (p == 0 || p == 1 || p == 2)

            return 1;

        return (getPadovan(p - 2) + getPadovan(p - 3));

    }

}

 

Padova

.


Related Discussions:- #Padovan string

Programming, Write a program that writes your name on the monitor ten times...

Write a program that writes your name on the monitor ten times. Write this program three times, once with each looping method.

201 it, overloadstream insertion opertator to display the data of object on...

overloadstream insertion opertator to display the data of object on the console

Procedure to add two numbers in a recursive manner, (a) Write a procedure c...

(a) Write a procedure called (add x y) that adds two numbers in a recursive manner. Specifically, note that x + y = (x + 1) + (y - 1) and x + 0 = x. (b) Using the substitution m

Program for stack over flow vulnerability., Imagine that the server program...

Imagine that the server program is a setuid program owned by the root, then after you penetrate the program with a shell running, you become the ROOT and you can remove the whole f

Describe the theoretical concepts of binary files, Question 1 Explain the ...

Question 1 Explain the concept of constructors and destructors in C++ with programming examples Question 2 Explain the concepts and applications of multiple inheritance and v

Constructor, Why copy constructor accepts reference to an object and not t...

Why copy constructor accepts reference to an object and not the object itself, whether ah hence it we do otherwise

Logic, to calculate the amount to be paid by a customer buying yummy cupcak...

to calculate the amount to be paid by a customer buying yummy cupcakes for his birth day party

Prime no., program to find if a no . is prime or not

program to find if a no . is prime or not

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd