#Padovan string, C/C++ Programming

Assignment Help:

A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of the characters ‘X’ , ‘Y’ and ‘Z’ only, and given value of n, write a program that counts the number of occurrences of the string in the n-th Padovan string P(n)

 

program in java

// aakash , suraj , prem sasi kumar kamaraj college
program 1 :

package test.padovanstring;

public class PadovanString {
    public int stringOccurrences(int n, String str){
   
    if(n >= 40)
    return -1;
    if(str.replaceAll("X|Y|Z","").length()>0)
    return -1;
    String res=pad(n);
    return(res.length() - res.replaceAll(str,"").length())/(str.length());
    }
public String pad(int n){
    if(n == 0) return "X";
    if(n == 1) return "Y";
    if(n == 2) return "Z";
    else return pad(n-2) + pad(n-3);
   
}
    public static void main(String []args)
    {
        PadovanString p = new PadovanString();
        System.out.println(p.stringOccurrences(21,"YZ"));
    }
}

 

 

 

Program set 2 :

import java.util.Scanner;

import java.util.ArrayList;

 

public class PadovanSeries

{

    public static void main(String[] arg)

    {

        Scanner read = new Scanner(System.in);

        System.out.println("Enter starting no. : ");

        int start = read.nextInt();

        System.out.println("Enter ending no. : ");

        int end = read.nextInt();

        int[] ans = getSeries(start, end);

        System.out.println("Padovan series : ");

        for (int a : ans)

            System.out.print(a + " ");

    }

 

    public static int[] getSeries(int s, int e)

    {

        ArrayList list = new ArrayList();

        int i, j = 0;

        for (i = s; i <= e; i++, j++)

            list.add(getPadovan(i));

        int[] ans = new int[j];

        for (i = 0; i < j; i++)

            ans[i] = list.get(i);

        return ans;

    }

 

    public static int getPadovan(int p)

    {

        if (p == 0 || p == 1 || p == 2)

            return 1;

        return (getPadovan(p - 2) + getPadovan(p - 3));

    }

}

 

Padova

.


Related Discussions:- #Padovan string

What should one catch?, A: By keeping along with the C++ tradition of "ther...

A: By keeping along with the C++ tradition of "there's more than one method to do that" (translation: "give programmers options & tradeoffs so they can choose what's best for them

Object irientation, Explain about the strategies of implementation of the s...

Explain about the strategies of implementation of the statecharts, Database Management System?

Sort wars, Explain each of the algorithms in a way that would be understand...

Explain each of the algorithms in a way that would be understandable to an intelligent person who is not familiar with programming. You should not use any code (or even pseudo code

Area under curve, Write a program to find the area under the curve y = f(x)...

Write a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b.     #include float start

Described overriding?, In order to override a method, a subclass of the cla...

In order to override a method, a subclass of the class which originally declared the method have to declare a method along with the same name, return type (or a subclass of that re

Car rental project, I need a project on car rental system using c programmi...

I need a project on car rental system using c programming only of college level

I need p2p video streaming, Project Description: P2P media streaming bro...

Project Description: P2P media streaming browser (IE, Chrome, Firefox) plug-in needed that is compatible with Win Xp,7,8 that is Windows Firewall friendly Example like Swarm

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd