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Minor page fault :If the page is loaded in memory at the time the fault is started, but is not checked in the memory management unit as being loaded in memory, then it is named a minor or soft page fault. The page fault handler in the operating system merely needs to create the entry for that page in the memory management unit point to the page in memory and show that the page is loaded in memory; it does not require reading the page into memory. This would happen if the memory is shared by different process and the page is already send into memory for other process. The page could also have been replaced from a process's Working Set, but not yet erased to disk or written, such as in operating system machines that use Secondary Page Caching. Since these faults do not call disk latency, they are faster and less cost effective than major page faults.
List three ways of allocating storage, and give advantages of each. a. Contiguous allocation. Fastest, if no changes are to be made. Also simplest for random access files. b
breifly write a note on about evolution of operating system?
Define caching. A cache is a region of fast memory that holds copies of data. Access to the cached copy is well-organized than access to the original. Caching and buffering are
Explain with an example the need of Shift Alteration in critical section problem? Consider processes P i and P j and consider the algorithm for P i and P j .
What is co-operative process? A process is co-operating if it can influence or be affected by the other processes implementing in the system. Any process that share data with o
How is memory management done using bit maps? A bit map is here in this we signify the bit value as 0 or 1. 1-hole 0-process In this we are able to represent the proce
Q. Presume that you have coded the deadlock-avoidance safety algorithm as well as now have been asked to implement the deadlock-detection algorithm. Can you do thus by simply usin
Q. Explain a mechanism by which one segment could belong to the address space of two different processes. Answer: Because segment tables are a collection of base-limit register
Question: A set of processes are in a deadlock state when every process in the set is waiting for an event that can be caused by only another process in the set. (a) There
Questiion 1 What is RTOS? What are its requirements? Questiion 2 Explain the structural elements of a real time system mode Questiion 3 What is kernel? Explain abo
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