Minimum volume of sump volume for pumps, Civil Engineering

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Minimum volume of sump volume for pumps

Maximum pumping rate = QP

Volume of sump = V

Inflow Rate = Qi

Cycle Time Tc= t1 + t2

t1 = V / QP - Qi

t2 = V / Qi

Tc = Minimum Cycle Time

V = Tc / {1/ (QP - Qi) + 1 / Qi}

For Minimum Volume,

δV / δQi = δ/δQi[Tc / {1/ (QP - Qi) + 1/ Qi}]

Minimum Volume occurs when Qi = 0.5Qp

Hence, Minimum Volume of sump = Tc / {1/ (QP - 0.5Qp) + 1/0.5Qp}

            = Tc QP / 4


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