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Minimise the logic function F (A, B, C, D) = Π M (1, 2, 3, 8, 9, 10, 11,14) ⋅ d (7, 15)Use Karnaugh map. Ans. Given function F=∏M(1,2,3,8,9,10,11,14).d(7, 15)F'=B'D+B'C+AC+AB' By Complementing FF=(B'D+B'C+AC+AB')'= [(B'D)'(B'C)'(AC)'(AB')']'= (B+D')(B+C')(A'+C')(A'+B)Taking here complement twice but also without opening the bracketF=[(B+D')+(B+C')'('A'+C')+(A'+B)]'
Hashed strings can often be deciphered by 'brute forcing'. Bad news, eh? Yes, and particularly if your encrypted passwords/usernames are floating around in an unprotected file some
i just want the experiment to be taken , on Grid Security........
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HCP
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