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If the data set contains an odd number of items, the middle item of the array is the median. If there is an even number of items, the median is the average of the two items. If the total of the frequencies is odd, say n, the value of the (n+1)/2th item gives the median and when the total of the frequencies is even, say, 2n, then nth and (n + 1)th are two central items and the arithmetic mean of these two items gives the median.
The following data relates to the sales figures of certain companies relating to the year 2000-2001:
Companies
Sales
ACC
1520
Andhra Valley
436
Excel Inds
228
Indian Hotels
239
Tata Hydro
292
Tata Power
734
Tata Tea
412
Voltas
980
Tomco
312
Tinplate Co.
256
The median for the above data can be obtained as follows:
The series should first be arranged in an appropriate order. In the present case it is in descending order.
Company
Rank
1
2
3
4
5
6
7
8
9
10
Now, median is the mean of the 5th and the 6th items, i.e. (412 + 312)/2 = 362.
Thus, the median sales value of the ten companies is 362.
f(x,y)=c(6-x-y) ,o find P(X+Y
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