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A car travels along a horizontal circular curved road that has a radius of 600 m. If the speed is uniformly increased at a rate of 2000 km>h2, determine the magnitude of the acceleration at the instant the speed of the car is 60 km>h.
Ans) a2=(ar)2+(at)2
a2=v2/r+(2000km/hr2)2
a2=36000000+4000000
a=6.32*103
#question. third law of motion.
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if acceleration vs time graph is given then how to calculate displacement
a2 = (v2/r)2 + aT = (3600/0.6)2 + (2000)2 = (6000)2 + (2000)2 = 40*106 a≈6.32*103 km/h2
a2 = (v2/r)2 + aT = (3600/0.6)2 + (2000)2 = (6000)2 + (2000)2 = 40*106
a≈6.32*103 km/h2
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