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∫1/sin2x dx = ∫cosec2x dx = 1/2 log[cosec2x - cot2x] + c = 1/2 log[tan x] + c Detailed derivation of ∫cosec x dx = ∫cosec x(cosec x - cot x)/(cosec x - cot x) dx = ∫(cosec 2 x
Problem 1 Work through TALPAC 10 Basics (refer to attached handout). Answer the set of questions at the end of tutorial module. Problem 2 Referring to both the haul cyc
what is the trignomatry ratio
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A 25 foot ladder just reaches the top of a house and forms an angle of 41.5 degrees with the wall of the house. How tall is the house?
3. How are Indian customers visiting Shoppers’ Stop any different from customers of developed western countries? 4. How should Shoppers’ Stop develop its demand forecasts?
the base b of a triangle increases at the rate of 2cm per second, and height h decreases at the rate of 1/2 cm per second. Find rate of change of its area when the base and height
limit x-a/|x-a| equals x-a [a]a [b]0 [c]-a [d]none 0f these
2+2=
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