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A particle executes linear some with an amplitude if 2 cm.when the particle is at 1cm from the mean position the magnitude of its velocity is equal to that of its acceleration.Then its time period is?Ans) velocity at distance x in shm is given as v= w sqrt(A2-x2)so A = 2 x =1v = w sqrt(4-1) = wsqrt3now acc at distance x is a= w2 x = w2as mag a = mag vw2 = wsqrt3w= sqrt32pi/T= sqrt3T = 2pi/sqrt3
We here at Brilliant assume that you work through these problems using some sort of writing utensil. Take your pen or pencil, balance it on its tip, and let go. It falls over. How
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