The Null Hypothesis - H0: β0 = 0, H0: β1 = 0, H0: β2 = 0, Βi = 0
The Alternative Hypothesis - H1: β0 ≠ 0, H0: β1 ≠ 0, H0: β2 ≠ 0, Βi ≠ 0 i =0, 1, 2, 3
Reject H0 if |t | > t?¹ = 1.96155 or Reject H0 when P-value ≤ α = 0.05
Predictor Coef SE Coef T P VIF
Constant 0.37593 0.01341 28.04 0.000
totexp -0.00131710 0.00005581 -23.60 0.000 1.045
age 0.0016462 0.0003019 5.45 0.000 1.038
nk 0.031672 0.004676 6.77 0.000 1.007
Inverse Cumulative Distribution Function
Student's t distribution with 1499 DF
P( X <= x ) x
0.975 1.96155
Since the constant = 28.04 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.
Since the totexp = -23.60 < 1.96155 (CV) and the P-Value is ≤ α = 0.05, there is evidence to suggest that H0 should be accepted according to the T value however the P-Value suggest otherwise but it is not significant.
Since the age = 5.45 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.
Since the nk = 6.77 > 1.96155 (CV) and the P-Value is ≤ α = 0.05, H0 would be rejected as there is sufficient evidence.