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The interval of validity for an IVP along with initial conditions:
y(t0) = y0 or/and y(k)(t0) = yk
There is the largest possible interval on that the solution is valid and contains t0. Such are easy to describe, but can be tough to find, thus I'm going to put off saying anything more regarding these till we get into in fact solving differential equations and require the interval of validity.
how it will be ? = ? + Ø
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3 2/3 - 1/6
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