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Inorder traversal: The left sub tree is visited, then the node and then right sub-tree.
Algorithm for inorder traversal is following:
Figure: An expression tree: An inorder traversal
Inorder traversal can be best explained by an expression tree, where the operators are at parent node & operands are at leaf nodes.
Let us assume the above expression tree .The postorder , preorder, and inorder traversal are following:
preorder Traversal : + * / 4 2 7 - 3 1
postorder traversal : 4 2 / 7 * 3 1 - +
inorder traversal : - ((((4 / 2) * 7) + (3 - 1))
There is another tree traversal (certainly, not very common) is called level order, where all the nodes of the similar level are first travelled starting from the root .
Figure: Tree Traversal: Level Order
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Problem Your LC code is stored in a memory location as shown and the variable name is LC LC Memory address Content(LC code)
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Ans: A procedure to reverse the singly linked list: reverse(struct node **st) { struct node *p, *q, *r; p = *st; q = NULL; while(p != NULL) { r =q;
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