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The Diamond Structure
The diamond cubic structure is a distinctive of materials that have its constituent materials bound in tetrahedral bonds. Insulators like carbon, semiconductors like Germanium, Silicon etc exhibit this crystal structure. The diamond structure is an FCC with a two atom basis. If one atom of the basis is at the FCC lattice point, say (0,0,0) the other atom of the basis is at (¼ a, ¼ a, ¼ a ) where a is the lattice constant of the FCC lattice. Thus the diamond structure can be arrived at by attaching one atom to each FCC lattice point (x,y,z) and the other at a point ( (x+a/4), (y+1/4), (z+a/4) ).
A Plane polarized light is incident on a piece of quartz cut parallel to its axis. Evaluate the least thickness for which ordinary ray and extraordinary ray combine
is terrestrial telescope a concave or convex?
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Assumptions: Kinetic Energy=KE, Potential Energy=PE m=mass of the skateboarder=55 kg, Velocity v=1.80m/s So ,Initial Energy(KE) of the skateboarder=mv 2 /2 = 0.5* 55 * (1.8)^
A simple calorimeter Small soup tins can be found which fit loosely into a 1lb. jam jar. If the top of the tin is cut off cleanly with a rotary type opener it serves as an good
a body is thrown horizontally with a velocity of u from the top of a tower. the displacement of the stone when the horizontal and vertical velocities are equal is
#Need help integrating a=d^2/dt^2
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