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C language lets us do this in a structure definition by putting: bit length after the variable that is.
struct packed_struct { unsigned int f1:1; unsigned int f2:1; unsigned int f3:1; unsigned int f4:1; unsigned int type:4; unsigned int funny_int:9;} pack;
Here the packed_struct contains 6 members: Four 1 bit flags f1..f3, a 4 bit type and a 9 bit funny_int.
C language automatically packs the above bit fields as compactly as possible provided that the maximum length of the field is equal or less than to the integer word length of the computer. If this isn't the case then some compilers may permit memory overlap for the fields whilst other would store the next field in the next word.
Access members as usual via:
pack.type = 7;
how to use and what is implicit and explicit constructor
Employ operator () instead of operator[]. While you have multiple subscripts, the cleanest way to do it is along with operator () instead of with operator[]. The reason is that
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Mixed Mode Expressions and Implicit type Conversions A mixed mode expression is one in which the operands are not of the similar type. In this case, the operands are converted
The Shift Operators There are 2 shift operators : left shift ( >). These are binary operators. The format is operand >> number or operand The first
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A: They are following: Const: point out that memory once initialized, must not be modify through a program. Volatile: denote that value in the memory location can be modified
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