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If tanx+secx=sqr rt 3, 0 Ans) sec2x=(√3-tanx)2 1+tan2x=3+tan2x-2√3tanx 2√3tanx=2 tanx=1/√3 x=30degree
Ans) sec2x=(√3-tanx)2
1+tan2x=3+tan2x-2√3tanx
2√3tanx=2
tanx=1/√3
x=30degree
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squaring both the sides,tan2x + sec2x +2tanxsecx = 3put sec^2x = tan2x +1and take 2tanx common,2tanx(tanx+sec)=2sqrrt3(tanx)=1therefore tanx = 1/rt3x=30
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