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A: Use operator overloading to present a friend left-shift operator, operator<<.
#include class Fred {
public:
friend std::ostream& operator<< (std::ostream& o, const Fred& fred);
... private:
int i_; // only for illustration
};
std::ostream& operator<< (std::ostream& o, const Fred& fred)
{
return o << fred.i_;
}
int main()
Fred f;
std::cout << "My Fred object: " << f << "\n";
...
We employ a non-member function (a friend in this case) as the Fred object is the right-hand operand of the << operator. If the Fred object was imagined to be on the left hand side of the << (i.e., myFred << std::cout instead of std::cout << myFred), we could have utilized a member function named operator<<.
Note down that operator<< returns the stream. It is so the output operations can be cascaded.
Virtual Base Classes This ambiguity can be resolved if the class derived have only one copy of the class base. This can be done by making the base class a virtual class. This k
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