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A ball dropped from a balloon at rest clears a tower 81m high during the last quater second of its journey. Find the height of the balloon and the velocity of the body when it reaches the ground.WHAT IT MEANS- LAST QUATER SECOND OF ITS JOURNEY. Solution) The last quarter of the jouney menas 1/4th of the total time it requires in its total journey.Let total time be 4t, u = 0.So, v at 3t = 3gt, and at 4t = 4gt.by v² = u² + 2as,16g²t² = 9g²t² + 2g(81)7g²t² = 162g7gt2 = 162t² = 162 / 7gt = 1.5 sec.but time is 4t = 6 sec.So velocity on reaching = 4gt = 58.8 m/sWith this velocity, height of fall = 2t(58.8) = 705.6m
A body has a weight W kg on the surface of earth. What will be its weight on the surface of moon in gravitational units of force and SI units? Ans) mass of body=W/g At moon w
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One mole of an ideal gas at 0°C is compressed adiabatically reversibly to a pressure of 20 times its initial pressure. Evaluate the final temperature.(γ=1.4)
Q Define: Drift velocity. Drift velocity is described as the velocity with which free electrons get drifted towards the positive terminal, when an electric field is applied.
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