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Q. Geosynchronous Orbit
Communications satellites are able to be placed in equatorial orbits at a distance which results in an orbital period of one day. Therefore the satellite occupies a stationary position above the surface of the earth. To determine the height of this orbit we simply equate the centripetal force due to gravity with the centrifugal force resulting from motion along the circular path. Using Me for the mass of the earth and ms for the mass of the satellite, G for the gravitational constant ω for the angular velocity and h for the height of the orbit above the earth's surface
We have
GMems/(Re + h)2= msω2(Re + h)
Then
This is 22,300 mi and quantity to about 5.6 earth radii.
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Q State Ohm's law. At a steady temperature that the steady current flowing through a conductor is directly proportional to the potential difference between the two ends of the
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discussion
Two steel balls are at a distance S from one another. As the mass of ONE of the balls is doubled, the gravitational force of attraction between them is: a) Quartered b) H
can i get assistance here with questions involving the design of a permanent magnet magnetic bearing?
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