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Q. Geosynchronous Orbit
Communications satellites are able to be placed in equatorial orbits at a distance which results in an orbital period of one day. Therefore the satellite occupies a stationary position above the surface of the earth. To determine the height of this orbit we simply equate the centripetal force due to gravity with the centrifugal force resulting from motion along the circular path. Using Me for the mass of the earth and ms for the mass of the satellite, G for the gravitational constant ω for the angular velocity and h for the height of the orbit above the earth's surface
We have
GMems/(Re + h)2= msω2(Re + h)
Then
This is 22,300 mi and quantity to about 5.6 earth radii.
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