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FRAGMENT IDENTIFICATION:
IDENT field in every fragment matches IDENT field in real datagram. Fragments from different datagrams may arrive out of order and still be saved out.
FRAGMENT LOSS:
IP may drop fragment because receiver drops whole original datagram. Destination sets timer with every fragment to check lost fragment. If timer ends before all fragments reach, fragment is assumed lost and datagram is removed. Host is assumed to retransmit.
FRAGMENTING A FRAGMENT:
Fragment may checks subsequent network with even smaller MTU. Router segments the fragment to fit. Resulting sub-fragments look just like real fragments. There is no use to reassemble hierarchically as sub-fragments add position in real datagram.
Q. Attacks on wireless network WSN are vulnerable to attacks which compromise the integrity of the WSN nodes by decreasing the nodes' fault tolerance capabilities, data distrib
CSMA/CA Wireless needs collision avoid ness rather than collision checking. Transmitting computer puts very short codes to receiver. Receiver responds with short message getti
FRAGMENTATION AND PATH MTU IPv6 source is responsible for fragmentation. Routers simply drop datagrams bigger than network MTU. So source have to fragment datagram to arrive d
a) determine the RTT (round trip time) between a client requesting a web page of 1024 bytes in size from an internal web server on a 100 Base-T Ethernet. Assume a one-way propagati
TRANSPORT PROTOCOLS: Give application-to-application communication. Require extended addressing mechanisms to check applications. Are known end-to-end communicatio
There is another probing methods i-e Trace Route. To get more detail it is used As given in the figure about the route to DANDELION-PATCH.MIT.EDU was looked out a
LOG FILE MONITORS Log file monitor (LFM) is similar to NIDS. It reviews log files generated by servers, network devices, and even other IDSs for patterns and signatures. Pattern
QUESTION a) "Two of the key attributes of an enterprise network is that it have to be multi-platform and multisite." Decribe what you understand by this statement. b) A
(a) (i) Bob has public RSA key (n = 77, e = 7). Show that Bob's private key is (d = 43). (ii) Alice wants to send the message m = 13 to Bob. She encrypts the message usi
Please see attached file
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