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Finding Zeroes of a polynomial
The below given fact will also be useful on occasion in determining the zeroes of a polynomial.
Fact
If P (x) is a polynomial & we know that P (a) = 0 and P (b) = 0 then somewhere among a and b is a zero of P ( x ) .
According to this fact if we evaluate the polynomial at two points & one of the evaluations provides a positive value (that means the point is above the x-axis) & the other evaluation provides a negative value (that means the point is below the x-axis), then the single way to get from one point to the other is to go through the x-axis. Or, in other terms, the polynomial ought to have a zero, as we know that zeroes are where a graph touches or crosses the x-axis.
Notice that this fact doesn't tell us what the zero is, it just tells us that one will present. Also, note that if both of the evaluations are +ve or both evaluations are -ve there may or may not be a zero among them.
x-45=47
2x^4-11x^3+19x^2-13x+3
#questionSolve the system graphically. If the system has an infinite number of solutions, use set builder notation to write the solution set. If the system has no solution, state t
simplify the following expressions for the given values x3 -x2/x2 -x x=3 how do i do this to get answer need step by step instruction
classify 0.626539212
x=y=3 , 2x-y=5
i am in 6th grade..... and just test prep
x^2+6x+8=0
Example: Solve following equations. 2 log 9 (√x) - log 9 (6x -1) = 0 Solution Along with this equation there are two logarithms only in the equation thus it's easy t
y+5=(4x+1)
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