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Q. Find the Physical address of instruction?
Value of Instruction Pointer and holding address of instruction = 1234h
Value of code segment register (CS) = 448Ah
Physical address of instruction
Physical Address = CS (Hex) × 16 + IP
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How many two input AND gates and two input OR gates are required to realize Y = BD+CE+AB ? Ans. Here three product terms, therefore three AND gates of two inputs are needed.
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