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In parallelogram ABCD, ∠A = 5x + 2 and ∠C = 6x - 4. Find the evaluation of ∠A.
a. 32°
b. 6°
c. 84.7°
d. 44°
a. Opposite angles of a parallelogram are same in measure. Using this fact, ∠A = ∠C or 5x + 2 = 6x - 4. Subtract 5x from both sides; 2 = x - 4. include 4 to both sides; 6 = x. Now substitute x = 6 into the expression for ∠A; 6(6) - 4 = 36 - 4 or 32. If you select b, you solved for x, not the angle. If you select c, you considerd the angles were supplementary. If you select d, you considerd the angles were complementary.
would like explaination on how to do them
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