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Q. An X-ray diffraction of a crystal gave a closest line at an angle of 6o27'. If the wavelength of X-ray is 0.58Ao, find the distance between the two cleavage planes.
2d Sinθ = nλ
Here n = 1.
d = λ / 2 Sinθ
d = 0.58 / 2 X Sin 6o27'
d = 0.58 / 2 X 0.1123
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