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Q: A bar having length 25mm has varying cross section. It carries load of 14KN. Find out extension if cross section is given by (6 + x2/100) mm2 where x is distance from one end in cm. Take E = 200 GN/m2.
Sol.: Consider small element of length dx at distance x from small element. Because of tensile load applied at ends, element length dx elongates by small amount Δx, and
Δx = Pdx/AE = Pdx/[(6 + x2/100)]
The total elongation of the bar is then worked out by integrating the above identity between the limits
x = 0 to x = L
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