Explain the total magnetic flux in the ring, Physics

Assignment Help:

A coil of 600 turns is wound uniformly on a ring of non-magnetic material. The ring has a uniform cross-sectional area of 200mm2 and a mean circumference of 500mm. If the current in the coil is 4A, determine

(a) The magnetic field strength,

 (b) The flux density, and

 (c) The total magnetic flux in the ring.

 


Related Discussions:- Explain the total magnetic flux in the ring

Thermal equillibrium, a column of water contains fine metal particles of ra...

a column of water contains fine metal particles of radius 2*E(-8) m, which are in thermal equillibrium at 298 K. if there are 1000 particles per unit volume at a given height,how m

Explain fresnel diffraction, If either screen or source or both are at pres...

If either screen or source or both are at preset distance from the diffracting device (obstacle or aperture), the diffraction is known as Fresnel type.

Determine an expression for the current in the ring, Determine an expressio...

Determine an expression for the current in the ring jumping ring demonstration, an electromagnet provides magnetic field of B=0.2 cos 377t tesla over a circle of radius 1.2cm

Laser, what is the importance of laser?

what is the importance of laser?

Planck radiation law, Planck radiation law A law that defined blackbody...

Planck radiation law A law that defined blackbody radiation better than its predecessor, therefore resolving the ultraviolet catastrophe. It is depend on the supposition that e

Inertial and non inertial frame of refrence, What is inertial and non inert...

What is inertial and non inertial feame if refrence of reference?

ACTIVITY, IN SUCCESSIVE DISINTEGRATION WHY DOUGHTER ELEMENT NOT DECAY WHEN ...

IN SUCCESSIVE DISINTEGRATION WHY DOUGHTER ELEMENT NOT DECAY WHEN IT FORM BUT DECAY AFTER A FIEW TIME FROM ITS FORMATION

Find refractive index by using total internal reflection, Q. Illustrate how...

Q. Illustrate how do you find the refractive index of a liquid by using total internal reflection? Answer:- Using Snell's law n (1) = (n (2) x sin angle (2)) / sin angl

Why the centre of newtons rings pattern appears dark, Q. Why the centre of ...

Q. Why the centre of Newton's rings pattern appears dark? The thickness of the air film becomes zero at the point of contact of lens L with glass plate P. Therefore there is no

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd