Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Power is to be supplied from a source whose resistance is 20 K ? to a load of 100 ?. Would you consider it as a constant voltage source or current source? Explain.
Ans.
Given source is considered as a constant current source because, a source that has a very high internal resistance (20 K?) as compared to the load resistance (100 ?) is a constant current source.
Explanation: In figure below, a load impedance ZL is connected to a current source. Let It be the short-circuit current of source, and Zs be its internal impedance. Current IS is splitted into two parts IL through ZL and I1 through ZS. That is
IS= I1+ IL
Or I1= IS- IL
Because impedance Zs and ZL are in parallel, voltage drop across each must be equal, i.e.,
The above equation determines us that load current IL would remain almost the same as current IS, provided the ratio ZL/ZS= 100/20000 = 1/200 is small compared to unity. Source then behaves as a good current source. Or we can say, the larger the value of internal impedance ZS (20K?) compared to load impedance ZL (100?), the smaller is the ratio ZL/ZS, and better it works as a constant current source.
Path of a projectile The apparatus below can be used to indicate the independence of the horizontal and vertical velocities of a projectile. The projectile is a metal ball, and
Bell's inequality (J.S. Bell; 1964) A quantum mechanical theorem shows that if quantum mechanics were to rely on hidden variables, it ought to have nonlocal properties.
A helicopter is ascending vertically with a constant speed of 6 meters per second relative to the ground. At the instant the helicopter is 60 meters above the ground it releases a
When current is passed by a junction of two dissimilar solids, the temperature is either evolved or absorbed at the node. This effect is known as Peltier effect
Q. Find the effectual resistance between A and B. 1/R p = 1/R 1 + 1/R 2 R p = R 1 R 2 / (R 1 + R 2 ) = 15 X15 / 30 = 7.5 ohm
Coupling factor: If all the flux of a primary coil links with all the turns of a secondary then 100% coupling exists. Sometimes it is more convenient to use a coupling factor
energy mass relation
Question As-per to the law of reflection the angle of reflection is equal to the angle of incidence. An angle is at all times an angular separation between two planes a direct
The beam below is supported at A and B. F1 and F2 in kN are given in P21 and P22 respectively. F3 in kN is given in P23 and the couple in kN.m is given in P24. Assume that F1, F
Understand the manufacturing technique of optical fibres by using double crucible method. In double crucible method the inner platinum crucible has core material into molten fo
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd