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Function overloading:
Functions can be defined with same name. Depending upon the type of argument passed
the function will perform. This is known function overloading. It may look like calling the same function but really it is not. This is also called as function polymorphism.
int f_over(int x);
float f_over(float a, float b);
void main( )
{int a=10;
float x=11.11,y=22.2,z;
c =f_over(a); //The value of c is 10
}
{return (x)
};
float f_over(float x, float y)
{return (x/y);
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A: no, can't. The names of, precedence of, associativity of, and arity of operators is fixed through the language. In C++, there is no operator** so you cannot create one for a
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Each function has its own stack frame between %fp and %sp. Let Caller calls Callee. Then Caller's %sp becomes callee's %fp, and callee's %sp set to be a new value (a smaller one be
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