Explain ferrites suitability for high frequency application, Electrical Engineering

Assignment Help:

Explain Suitability of ferrites for high frequency application.

Ferrites are extensively used in micro wave equipments and in computers. Ferrites are advantageous at high frequencies due to low eddy current losses. Ferromagnetic alloys cores and metals have to be eliminated in order to decrease the losses. At high frequencies laminations  should  be  so  thin  therefore  both  fabrication  and  assembly  become  costly processes. At such frequencies a duet core that consists of fine particles of ferromagnetic material insulated from each other may be utilized. But these have the disadvantage of diluting the ferromagnetic martial and reducing the effective relative permeability. Further disadvantage is that the flux density varies by the core because of non-uniform spacing of the particle. At certain points where there is greater concentration of particles; therefore flux density is probable to be higher entailing larger hysteresis losses.

For this purposes, Ferrites are used for the high frequency application

2163_Hysterisis Loop of Magnetic Materials.png

Hysterisis Loop of Magnetic Materials

A magnetic material is composed of magnetic dipoles oriented in random direction is zero. If a magnetic material is magnetized by applying a magnetizing force (i.e. MI), the magnetic dipoles begin orienting themselves towards applied magnetic force. As the magnetizing force is raised by increasing the magnetizing force, more and more of the magnetic dipoles become oriented. A stage comes while almost whole magnetic dipoles becomes oriented and as any increase in magnetizing force (MI) does not result in any increase in the dipoles getting oriented. Thus the magnetic field is established in the forward direction.

This stage of magnetization is termed as magnetic saturation as shown in figure. If the magnetizing force is slowly reduced this is found that the magnetic dipoles again get de-oriented, the rate of de-orientation now being small less than the rate of orientation at an exact magnetizing forces. Therefore the demagnetizing curve does not retrace back the magnetization curve as shown in figure (ii)

In figure (ii), OA is the magnetization curve and AB is the demagnetization curve. This may be seen that even while the magnetization force is reduced to zero, a small magnetization is left in the magnetic material. In the figure OB represents the residual magnetization. When the magnetizing force is applied now in the negative direction, a small amount of magnetizing force OC will be spent in fully de-magnetizing the material.  Further increase in magnetizing force will orient the magnetic dipoles in the opposite direction therefore establishing a magnetic field into the reverse direction.

While the magnetizing force is reduced to zero and after that again increased in the forward direction therefore the magnetization curve will follow the path DEA. The whole curve ABCDEA is termed as the hysteresis loop.


Related Discussions:- Explain ferrites suitability for high frequency application

What is occur in density flux state- ferromagnetic material, In a ferromagn...

In a ferromagnetic material the state of flux density is as follows when external magnetic field is applied to it. (A) Increased (B) Becomes zero (C) Remains unchang

Explain in detail the operation of 8255 in mode 1, Explain in detail the op...

Explain in detail the operation of 8255 in mode1 taking suitable example. In mode1, Ports A and B are programmed as input or output ports and Port C is used for handshaking.

Meter field testing - sealing points, Meter Field Testing - Sealing Points ...

Meter Field Testing - Sealing Points The meter seal should be tamper proof. The consumer should be briefed about seals. The sealing of all metering systems should be completed

Determine impedance - resultant current and power factor, Determine Impedan...

Determine Impedance - Resultant current and Power factor: In series R-L circuit, illustrated in Figure , Determine 1.      Impedance, 2.      Resultant current, 3.

Determine the peak frequency deviation, If an FM signal is given by s FM (t...

If an FM signal is given by s FM (t) = 100 cos [2πf c t +100 m(τ ) dτ ] and m(t) is given in figure, sketch the instantaneous frequency as a function of time and determine the pea

Chemical vapour deposition, Explain chemical vapour deposition method for t...

Explain chemical vapour deposition method for the preparation of nanomaterial and its properties

What is the physical length of this cable, Q. It is desired to cut a λ/4 le...

Q. It is desired to cut a λ/4 length of RG58A/U cable (ε r = 2.3) at 150MHz.What is the physical length of this cable?

Differentiate between n and p type semiconductors, Differentiate between n ...

Differentiate between n and p type semiconductors. n - Type semiconductor:- (i) If small amount of pentavalent impurity is added with, to a pure semiconductor giving a la

Compute the efficiency of the autotransformer, The single-phase, 50-kVA, 24...

The single-phase, 50-kVA, 2400:240-V, 60-Hz, two-winding distribution transformer is connected as a step-up autotransformer, as shown in Figure. Assume that the 240-V winding is pr

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd