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Explain deadlock detection algorithm for single instance of each resource type.
For single instance of each resource type the deadlock detection algorithm:
(i) Maintain a wait: In the graph nodes represent process. If process i is waiting for resource hold through process j. After that there is an edge from I to j.
(ii) Periodically invokes an algorithm which searches for cycles into the graph. If there is a cycle in the wait-for-graph so a dead lock is as exist in the system.
The logic circuit shown in the given figure can be minimised to Ans. The minimised figure of logic diagram is D, the output of the logic circuit is as Y=(X+Y')'+(X'+(X+
Define class P The class of all sets L that can be known in polynomial time by deterministic TM. The class of all decision problems that can be decided in polynomial time.
Explain in detail about Operating Systems (OS) Operating system (OS) is a program which after being initially loaded into computer by a boot program, manages all the other appl
Two computers using TDM take up turns to send 100-bytes packet over a shared channel that operates at 64000 bits per second. The hardware takes 100 microseconds after one computer
Purpose: Front line client service. Make bookings for vehicle servicing, accesses client database, prints invoices for clients etc. The mechanics complete worksheets for the variou
f(x)^2=f(x) - x
Before we take a detailed look about the Motorola 68HC11 series of micro controllers it is useful to define what is meant by a micro controller. As the name suggests a micro contro
Q. How are comparisons done in 8086 assembly language? There is a compare instruction CMP. Though this instruction just sets the flags on comparing two operands (both 16 bits
Bit Slice ALUs It was possible to manufacture smaller like 4 or 8 bits fixed point ALUs on a single IC chip. If these chips are constructed as expendable types then employing
Find the generating function to denote the number of ways the sum 9 can be acquired while 2 distinguishable fair dice are tossed and the first shows an even number and the second s
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