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Q. Explain basic working of Integrators?
Figure shows a noninverting integrator, which can be seen to be a negative impedance converter added with a resistor and a capacitor. Noting that vo = 2v1 and i3 = v1/R, the total capacitor current is
which shows that the circuit functions as an integrator.
Replacing R2 in the inverting amplifier of Figure by a capacitance C results in the somewhat simpler integrator circuit shown in Figure, known as an inverting integrator, or Miller integrator. With ideal op-amp techniques, iC = iin = vin/R. The voltage across C is just vo, so that
which illustrates that the network behaves as an integrator with sign inversion.
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Q Acharge of 0.1Cpasses through an electric source of 6 V from its negative to its positive terminals. Find the change in energy received by the charge. Comment onwhether the charg
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Q. For the circuit shown in Figure, develop and execute a PSpice program to obtain the node voltages and the current through each element.
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Q. Consider Figure of the weighted differencing amplifier. Let R 3 = R 1 and R 4 = R 2 . Determine the input resistance between terminals a and b of the circuit.
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