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Consider the relations described below: PHYSICIAN (regno, name, telno, city)PATIENT (pname, street, city) VISIT (pname, regno, date_of_visit, fee) Where the regno and pname identify the physician and the patient uniquely corresponding. Express queries (i) to (iii) in SQL.(i) Get the name and regno of physicians who are in Delhi.(ii) Find out the name and city of patient(s) who visited a physician on 31 August 2004.(iii) Get the name of the physician and the total number of patients who have visited her.(iv) What does the subsequent SQL query answer SELECT DISTINCT nameFROM PHYSICIAN PWHERE NOT EXISTS( SELECT *FROM VISITWHERE regno = p.regno )
(i) Select name, regno from PHYSICIAN where city = ‘Delhi'; (ii) Select pname, city from PATIENT,VISIT where PATIENT.pname=VISIT.pname and date_of_visit = '31-Aug-04'; (iii) select name, count(*) from PHYSICIAN, VISIT where PHYSICIAN.regno = VISIT.regno group by Physician . regno; (iv) This will provide the name of physicians who have not visited any patient.
Define the following constraints for the table client. (i) BAL_DUE must be at least 1000. (ii) NAME is a unique key. (i)ALTER TABLE CLIENT ADD CONSTRAINT CLIENT_BAL_DUE_C1
One-way Associations When an association is traversed only in the one direction, then it is implemented as a pointer i.e.an attribute which contains an object reference. If mu
can you resolve this for me please? Database Management Systems Homework 1 The following relations are given (primary keys are underlined): PLAY-ACTOR(AId, Name, Nationality, Birt
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Consider the following relational scheme: R (a,b,c,d,e,f) and its corresponding set of FDs {d→ a, be → c, ac → e, b → f, f → d, a → c}. a. Is the following decomposition i) non
Design a gennalization and specialization hierarchy for an automobile sales company
Define Atom of domain relational calculus An atom has the outline 1 , x 2 , ... , x n > -> r , in which r stands for a relation on n attributes and x 1 , x 2 , ... , x n ar
Define the Boyce-Codd Normal Form with instance and also Compare BCNF and 3NF. Ans: BCNF: For each functional dependency X->Y in a set F of functional dependencies over relati
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