Example of work- rate problems, Algebra

Assignment Help:

An office contains two envelope stuffing machines. Machine A can stuff a batch of envelopes within 5 hours, whereas Machine B can stuff batch of envelopes within 3 hours. How much time it take the two machines working together to stuff a batch of envelopes?

Solution

Let t is the time that it takes both of machines, working together, to stuff batch of envelopes. The word equation for problem is following,

1136_Example of Work- rate problems.png

However we know that the time spent working is t we don't know about the work rate of each machine. In order to get these we'll have to use the initial information given about how much time it takes each machine to do the job independently.  We can employ the following equation to get these rates.

1749_Example of Work- rate problems1.png

Let's begin with Machine A.

1 Job= ( Work Rate of A ) × (5) ⇒     Work Rate of A = 1/5

Now, Machine B.

1 Job = ( Work Rate of B) × (3)   ⇒   Work Rate of B = 1/3

Plugging these quantities in the main equation gives the following equation which we have to solve.

1/5 t +1/3 t = 1                                    Multiplying by 15 through both sides

3t + 5t = 15

8t = 15

t = 15/8 = 1.875 hours

Thus, it looks as it will take two machines, working together, 1.875 hours to stuff batch of envelopes.


Related Discussions:- Example of work- rate problems

Finding relations for given solutions, The slope is -3 and the y-intercept ...

The slope is -3 and the y-intercept is 4. How do I find a relation in the form y=mx+b which has a solution set line satisfying the given conditions?

Set, {a|a=9 ,a=N,a

{a|a=9 ,a=N,a

Horizontal shifts, Horizontal Shifts These are quite simple as well tho...

Horizontal Shifts These are quite simple as well though there is one bit where we have to be careful. Given the graph of f ( x ) the graph of g ( x ) = f ( x + c ) will be t

About rings, Prove that cosets of an ideal I in a ring R are disjoint or eq...

Prove that cosets of an ideal I in a ring R are disjoint or equal

Cubic function, Actually here we're not going to look at a general cubic po...

Actually here we're not going to look at a general cubic polynomial.  Here we are jsut going to look at f ( x ) = x 3 . Really there isn't much to do here other than only plugging

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd