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1. Suppose the datagram source allocates 12 bytes for this option. Then when the datagram leaves the source host, the RR option area will be like this:
7 12 4 00 0 0 00 0 0 0
2. At the ?rst router, the datagram may or may not be fragmented. The ?rst fragment (or the original datagram itself, if it was not fragmented) will be like this:7 12 8 0address 10 0 0 0
where "address1" is the IP address of the outgoing link at the router.
3. At the second router, the ?rst fragment (or original datagram) will be like this:7 12 12 0address 1address 2
4. At the third and all later routers (which don't exist in this assignment), no additional IP addresses would be recorded because there is no room. These later routers can tell there is no room because the "pointer" value (12) is equal to the available space value.
Consider a signal x(t) = 10 cos(2πfct + 4 cos 2πfmt). Assume frequency modulation. The message frequency fm = 2:3 kHz. Calculate the modulation index and find the bandwidth when
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Full-Duplex Ethernet 10Base5 as well as 10Base2 are half-duplex Full-duplex raises capacity of each domain No require for CSMA/CD
Length This is a 16 bit field that defines the total length of the user datagram, header plus data. This 16 bit can define a total length of a 0 to 65, 535 bytes.
Explain Asymmetric encryption
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ACK Received If an ACK is received by the sender. The SR sender marks that packet as having been received by the receiver.
Consider the following network example. Suppose that the distance vector (DV) routing algorithm is used to compute the distance between nodes. (a) Show the procedure of nod
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