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Solve (3x+ 1/ x + 4 ) ≥ 1.
Solution
The first thing that we have to do here is subtract 1 from both of sides and then get everything in a single rational expression.
(3x + 1/ x + 4) -1 ≥ 0
(3x + 1/x+4) - (x + 4/x+4) ≥ 0
(3x +1 - ( x + 4))/ x + 4 ≥ 0
2 x - 3 / x + 4 ≥ 0
In this case there is no factoring to do thus we can go straight to recognizing where the numerator & denominator are zero.
numerator : x = 3/2 denominator : x = -4
Following is the number line for this problem.
Okay, we desire values of x that give positive and/or zero in the rational expression. It looks like the outer two regions as well as x = 3/2 . As with the first instance we will have to avoid x = -4 since that will give a division by zero error.
Then the solution for this problem is,
-∞ < x < -4 and 3/2 ≤ x < ∞
( -∞, -4) and [3 , ∞ )
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4Log5n - log5m = 1 5log5m + 3log5m =14
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1/4-12
In the earlier section we looked at using factoring & the square root property to solve out quadratic equations. The problem is that both of these methods will not always work. Not
simplify the following expressions for the given values x3 -x2/x2 -x x=3 how do i do this to get answer need step by step instruction
5x8y+9x=0,y=5
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