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Solve (3x+ 1/ x + 4 ) ≥ 1.
Solution
The first thing that we have to do here is subtract 1 from both of sides and then get everything in a single rational expression.
(3x + 1/ x + 4) -1 ≥ 0
(3x + 1/x+4) - (x + 4/x+4) ≥ 0
(3x +1 - ( x + 4))/ x + 4 ≥ 0
2 x - 3 / x + 4 ≥ 0
In this case there is no factoring to do thus we can go straight to recognizing where the numerator & denominator are zero.
numerator : x = 3/2 denominator : x = -4
Following is the number line for this problem.
Okay, we desire values of x that give positive and/or zero in the rational expression. It looks like the outer two regions as well as x = 3/2 . As with the first instance we will have to avoid x = -4 since that will give a division by zero error.
Then the solution for this problem is,
-∞ < x < -4 and 3/2 ≤ x < ∞
( -∞, -4) and [3 , ∞ )
adding fractions
1/3h-4(2/3h-3)=2/3h-6
I need help with this equation: x^3 - 7x^2 + 5x + 35 = 0
To find the calorie density (D) in calories per ounce of food that contains c carories and weight w ounces is given by D=C/w
#If the common factor is known how do you find what the entire equation be (ex: A varies directly with t^2; A=8 when t=2. What is the formula?)
9
(5,7;y=1/3x+2
(y+1/3x)^2
a^x+2/a^5
In the earlier section we solved equations which contained absolute values. In this section we desire to look at inequalities which contain absolute values. We will have to exami
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