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Example of Log Rules:
Y = ½ gt2 where g = 32
Solution:
y = 16 t2
Find y for t = 10 using logs.
log y = log10 (16 t2)
log10y = log10 16 + log10 t2
log10y = log10 16 + (2 log10 t)
log10y = 1.204 + 2 log10 10
log10y = 1.204 + 2 x 1
log10y = 3.204
but this means 103.204 = y
y = 1600
i need some information on this topic for my holidays project..plz guide me what to do
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