Example of integration by parts - integration techniques, Mathematics

Assignment Help:

Example of Integration by Parts - Integration techniques

Illustration1:  Evaluate the following integral.

∫ xe6x dx

Solution :

Thus, on some level, the difficulty here is the x that is in front of the exponential.  If that was not there we could do the integral.  Notice also, that in doing integration by parts anything that we wish for u will be differentiated.  Thus, it seems that choosing u = x will be a good choice as upon differentiating the x will drop out.

Here that we've selected u we know that dv will be everything else which remains.  Thus, here are the choices for u and dv also du and v.

u = x    dv = e6x dx

du = dx           v = e6x dx = 1/6e6x

Then the integral is as follow:

∫ xe6x dx = x/6 e6x - ∫ 1/6 e6x dx

= x/6 e6x - 1/36 e6x + c

Just once we have completed the last integral in the problem we will add in the constant of integration to obtain our final answer.


Related Discussions:- Example of integration by parts - integration techniques

Slope-intercept form, Slope-intercept form The ultimate special form of...

Slope-intercept form The ultimate special form of the equation of the line is possibly the one that most people are familiar with.  It is the slope-intercept form.  In this if

Trignometry, verify 4(sin^4 30^0+cos60^0 )-3(cos^2 ?45?^0-sin^2 90^0 )=2

verify 4(sin^4 30^0+cos60^0 )-3(cos^2 ?45?^0-sin^2 90^0 )=2

The limit, The Limit : In the earlier section we looked at some problems ...

The Limit : In the earlier section we looked at some problems & in both problems we had a function (slope in the tangent problem case & average rate of change in the rate of chan

Second order differential equations, In the earlier section we looked at fi...

In the earlier section we looked at first order differential equations. In this section we will move on to second order differential equations. Just as we did in the previous secti

Help with word problem, You would like to have $4000 in four years for a sp...

You would like to have $4000 in four years for a special vacation following graduation by making deposits at the end of every 6 months in an annuity that pays 7% compounded semiann

Types of relation, Relations in a Set: Let consider R be a relation fro...

Relations in a Set: Let consider R be a relation from A to B. If B = A, then R is known as a relation in A. Thus relation in a set A is a subset of A ΧA. Identity Relation:

Find out that the relation is an equivalent relation or not, Let m be a pos...

Let m be a positive integer with m>1. Find out whether or not the subsequent relation is an equivalent relation. R = {(a,b)|a ≡ b (mod m)} Ans: Relation R is illust

Mensuration, find the diameter of circle whose circumference is 26.51

find the diameter of circle whose circumference is 26.51

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd