Entering a program-microprocessor, Assembly Language

Assignment Help:

Entering a Program

In this section, we will explain the procedure for entering a small program on IBM PC with DOS operating system. Assume a program of addition of 2 bytes, as already  described for hand coding. The similar program is written along with some syntax modifications in it for MASM.

Before beginning the process, make sure that all the files namely NE.COM (Norton's Editor, LINK.EXE (linker), MASM.EXE (Assembler), DEBUG.EXE (debugger) are available in the similar directory in which you are working. Start the procedure with the given command after you boot the terminal and enter the directory containing all the files mentioned.

C> NE

You will get display on the screen as in given figure.

Now type the file name. It will be displayed on the screen. Assume one types KMB.ASM as file name, the screen display will be as display as in given Figure.

1798_nortons editor.jpg

Press any of the keys, you will get following figure as the screen display.

2343_nortons editor2.jpg

Make a note of that, for every assembly language program, the extension .ASM ought to be there though every time the assembler does not use the entire name KMB.ASM and uses only KMB to handle the file, the extension indicate that it is an assembly language program file.  Even if you enter a file name without using the .ASM extension, the assembler searches for the file name but with .ASM extension and if it is not available, it gives the message 'File not found'. Once you get the display as in above Figure. You are free to type the program. One can use another type of command line as given.

C> NE KMB.ASM

The above command will give the display as in shown in above Figure directly, if KMB.ASM is a newly opened file. Or else, if KMB.ASM already present in the directory, then it will be opened and  then the program in it will be displayed. You can change it and save (command F3-E) it again, if you want the changes to be enduring. Or else, simply quit (command F3-Q) it to abandon the changes and exit NE. The entered program in NE looks similar to in given Figure. We have to just assume that it is an assembly language program to be assembled and Store it with command F3-E. It will produce a new copy of the program in the secondary storage. Then stop the NE with command F3-Q.

Once the above process is finished, you can now turn towards the assembling of the above program. Note that all of the commands and displays shown in this section are for Norton's Editor. Other editors may need some other commands and their display style may be rather different but the overall procedure is the similar.

Note that before quitting the editor program the newly entered or modified file ought to be saved, or else it will be lost and will not be available for further assembling procedure.

2498_nortons editor3.jpg


Related Discussions:- Entering a program-microprocessor

Port mapped or mapped input output, Port Mapped I/O or I/O Mapped I/O I...

Port Mapped I/O or I/O Mapped I/O I/O devices are mapped into a separate address space. This is generally accomplished by having a different set of signal lines to denote a mem

8088 timing system diagram-Microprocessor, 8088  Timing System Diagram ...

8088  Timing System Diagram The 8088 address/data  bus is divided  in 3 parts (a) the lower 8 address/data  bits, (b) the middle 8 address bits, and (c) the upper 4 status/

Any project ideas plz, can any one help me in my project by using assembly ...

can any one help me in my project by using assembly language

Boolean and comparison instructions, what will be the value of EAX after fo...

what will be the value of EAX after following instructions execute? mov bx, 0FFFFh and bx, 6Bh

The processor 8088-microprocessor, The processor 8088 The launching of ...

The processor 8088 The launching of the processor 8086 is consider as a remarkable step in the development of high speed computing machines. Before the introduction  of 8086 mo

Code for reading flow & generating serial output, Assembly Code for Reading...

Assembly Code for Reading Flow & Generating Serial Output The timer is timer 1 is set for the baud rate 9600, as the crystal used is of 11.0592 Hz.  Then the timer 1 is starte

Nible, calculate the number of one bits in bx and complement an equal numbe...

calculate the number of one bits in bx and complement an equal number of least significant bits in ax hint use the xor instruction

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd