Enter number of hours and find days, months and years.

echo -e "Enter Hours: \c"

read hr

echo "hour=$hr"

day=0

mon=0

yr=0

yr=`echo "$hr/365" | bc `

tmp=`echo "$hr%365" | bc`

mon=`echo "$tmp/30" |bc`

day=`echo "$tmp%30" | bc`

echo -e "$hr hours =  $yr years and  $mon months and  $day days"

Output

sh cnthour.sh

Enter Hours: 450

hour=450

450 hours =  1 years and  2 months and  25 days

sh cnthour.sh

Enter Hours: 370

hour=370

370 hours =  1 years and  0 months and  5 days