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This case will lead to similar problem that we've had all other time we've run in double roots or double eigenvalues. We only find a single solution and will require a second solution. In this case this can be demonstrated as the second solution will be,
y2(x) = xr In x
and therefore the general solution for this case is,
y(x) = c1 xr + c2 xr ln x = xr (c1 + c2 ln x)
We can again see a purpose for requiring x>0. If we didn't we'd contain all sorts of problems along with this logarithm.
Write a function called withdraw (in the file 'withdraw.m') that simulates withdrawing money from a bank account. The function takes a single input argument, a positive scaler doub
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Name : Jaya Malathy IC No : 99011460923 Quiz 1 : 20.5 Quiz 2 : 22.5 Quiz 3 40.5 Total marks = 83.5 Name IC No Quiz1 Quiz2 Quiz3 Grade --- ---- ---- ---- ---- ---- Jaya 990
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