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Differentiate between Nonpersistent and 1-persistent
Nonpersistent: If the medium is idle, transmit; if the medium is busy, wait an amount of time drawn from a probability distribution and then check the medium.
1-persistent: If the medium is idle, transmit; if the medium is busy continue to listen unless the channel is sensed idle; then transmit immediately.
Chaining In this method, instead of hashing function value as location we use it as an index into an array of pointers. Every pointer access a chain that holds the element havi
Krushkal's algorithm uses the concept of forest of trees. At first the forest contains n single node trees (and no edges). At each of the step, we add on one (the cheapest one) edg
Q. Illustrate the steps for converting the infix expression into the postfix expression for the given expression (a + b)∗ (c + d)/(e + f ) ↑ g .
In this project you will write a program to produce a discrete time simulation of a queue as shown in Fig. 1. Time is slotted on the input and the output. Each input packet follows
A Stack has an ordered list of elements & an array is also utilized to store ordered list of elements. Therefore, it would be very simple to manage a stack by using an array. Thoug
1. Define the following terms in a rule-based expert system? a) Knowledge base b) Inference engine 2. What is a fuzzy rule? Explain the difference between classical and fuzzy
Q. Explain the technique to calculate the address of an element in an array. A 25 × 4 matrix array DATA is stored in memory in 'row-major order'. If base address is 200 and
Arrays are simple, however reliable to employ in more condition than you can count. Arrays are utilized in those problems while the number of items to be solved out is fixed. They
What is a Binary Search Tree (BST)? A binary search tree B is a binary tree every node of which satisfies the three conditions: 1. The value of the left-subtree of 'x' is le
Inorder traversal: The left sub tree is visited, then the node and then right sub-tree. Algorithm for inorder traversal is following: traverse left sub-tree visit node
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