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A 0.500 kg stone attached to the end of a string is whirled in a vertical circle of radius 1,20 meters. The center of the vertical circle is 1.50 meters above the ground. When the stone is at the top of the circle, the tension in the string is 1.80 N. If the string is released at that point, where does the stone hit the ground? In other hand, what are the x and y coordinates of the position where the stone hits the ground? Note: place the origin of your coordinate system at the center of the vertical circle.
The current is an RL circuit drops from 1.1 A to 13 mA in the first second following removal of the battery from the circuit. If L is 12H, find the resistance R in the circuit.
Why does the charge on the outer surface of a parallel plate capacitor doesn't change when it is connected by a battery. only inner surface charge gets affected. Why??
Two stable isotopes of lithium and have respective abundances of 7.5% and 92.5%. These isotopes have masses 6.01512 u and 7.01600 u, respectively. Find the atomic mass of lithium.
9 kg of mercury is powred into a a glass u tube of uniforminternal diameter of 1.2 cm it oscilates freqently about its equilibrium pojistion claculate the time period
Precaution to minimize Radiation Danger: 1. One should keep safe distance away from radiation emitting source. 2. The radiation from the reactor are shielded by thick concr
Two thin convex lenses of focal lengths 0.15m and 0.2m are separated by a distance of 0.6m. Determine the effective focal length of the combination.
A small spool and a large spool Using nails for axles fasten a large spool and a smaller spool to a block of wood. Slip a rubber band in excess of both spools. Turn the larger
what is needed to make assignment on electromagnetism?
Schwarzschild radius The radius r of the event horizon for Schwarzschild black hole of mass m is provided through (in geometrized units) r = 2 m. In conventional units, r =
A particle is projected from ground with velocity 40sqrt2m/s.find- a)velocity and b)displacement of particle after 2sec .Take g=10m/s^2 Ans) velocity v=u+at a=-g v=40√2-10*2
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