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A 0.500 kg stone attached to the end of a string is whirled in a vertical circle of radius 1,20 meters. The center of the vertical circle is 1.50 meters above the ground. When the stone is at the top of the circle, the tension in the string is 1.80 N. If the string is released at that point, where does the stone hit the ground? In other hand, what are the x and y coordinates of the position where the stone hits the ground? Note: place the origin of your coordinate system at the center of the vertical circle.
I need help with the Fb = F2-F1 formula that used in buoyant force
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