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In the circuit shown in Figure, with the switch in position 1, the capacitor is uncharged.
If he switch is moved to position 2 at time t =0s, measure
(i) The initial current through the 0.5MΩ,
(ii) The voltage across the capacitor when t =1.5s, and
(iii) The time taken for the voltage across the capacitor to reach 12V
It makes sense that copper should be used because it could heat up faster, making the event more efficient.
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