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Determine the value of maximum power:
Determine the value of load resistance, RL for which the source shall transfer the maximum power. Also determine the value of maximum power.
Solution
Primary we apply the Thevenin theorem and draw the Thevenin's equivalent circuit. Eliminate the load resistance RL.
Calculation for VTH :
VTH = Open circuit voltage across load terminals AB, and
= VAB
VAB = VTH
= - 5 + 4 i
=- 5 + 4 ( 10/6)
= 1.66 Volt
Calculation for RTH :
Replace all of the sources by internal resistance. (Internal resistance of ideal voltage source is zero)
RTH = RAB
= 2 // 4 + 6
= (2 × 4 )/(2 + 4) + 6
= 7.33 Ω
Thevenin's Equivalent Circuit
According to maximum power transfer theorem
RL = RTH = 7.33 Ω
iL = 1.66 / (7.33 + 7.33) = 0.1132 Amp
Maximum power Pmax =( i L )2 × RL
= 0.09398 Watts
= 93.98 m Watts
The resistance of 1.5 km of wire of cross-sectional area 0.17 mm 2 is 150Ω. Determine the resistivity of the wire.
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